OpenStax, Algebra and Trigonometry 2e §11.7 Solving Systems with Inverses · Exercise 4 · Linear Algebra · Matrices

Solving Systems with Inverses · Exercise 4

In a previous section, we showed that matrix multiplication is not commutative, that is, $A B \neq = B A$ in most cases. Can you explain why matrix multiplication is commutative for matrix inverses, that is, $A^{- 1} A = A A^{- 1} ?$

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OpenStax, Algebra and Trigonometry 2e · §11.7 Solving Systems with Inverses · Exercise 4

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