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Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) §11.5 Linear Algebra, #31 · Linear Algebra · Matrices

After elimination solve for … (back substitution)

Eliminate $x$ from the last two equations by subtracting the first equation. Then eliminate $y$ from the new third equation by using the new second equation:

(a) $x + y + z x + 3 y + 3 z x + 3 y + 7 z = 2 = 0 = 2$ \hspace{2cm} (b) $x + y x + z y + z = 1 = 3 = 5.$

After elimination solve for $z, y, x$ (back substitution).

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Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) · §11.5 Linear Algebra, #31

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