| 133240 | The same pessimist would redraw Figure 5.2 with heights | Medium | |
| 133242 | The optimist and pessimist arrive at the same limit as years are… | Medium | |
| 133243 | (Important) Let … be the area under the … curve, above the… | Medium | |
| 133244 | Draw the … curve from … to … and put triangles below… | Medium | |
| 133248 | The accountant uses 2-year intervals and computes … at the midpoints (the… | Medium | |
| 133270 | The areas include a factor …, the base of each rectangle | Medium | |
| 133274 | Draw an example where three lower rectangles under a curve (heights …)… | Medium | |
| 133278 | Find the area under the parabola … from … to | Medium | |
| 133280 | Draw … so that the area … increases until …, stays constant… | Medium | |
| 133307 | Verify that … is … by checking … and | Medium | |
| 133309 | Find … in the formula | Medium | |
| 133311 | Add … to the table for … and compute | Medium | |
| 133312 | Add … and … to the table for | Medium | |
| 133313 | Guess … in the formula | Medium | |
| 133315 | Let … be the sum … of the (infinite) geometric series | Medium | |
| 133381 | … (take …) | Medium | |
| 133383 | | Medium | |
| 133384 | … (take …) | Medium | |
| 133385 | With … in 19–22, find the maximum … and minimum … and… | Medium | |
| 133386 | | Medium | |
| 133387 | | Medium | |
| 133388 | | Medium | |
| 133389 | | Medium | |
| 133390 | Repeat 19 and 20 with … and compare with the correct answer | Medium | |
| 133391 | The difference … in 21 is the area … of the far… | Medium | |
| 133393 | Find the Riemann sum … for … in Remark 1, when … | Medium | |
| 133410 | If … and … then the average of … from … to… | Medium | |
| 133412 | (a) Which property of integrals proves | Medium | |
| 133413 | What function has … (from 0 to …) equal to … at… | Medium | |
| 133414 | (a) If … is increasing, explain from Property 6 why … for… | Medium | |
| 133416 | If the positive numbers … approach zero as … prove that their… | Medium | |
| 133417 | Find the average distance from … to points in the interval | Medium | |
| 133419 | A point … is chosen randomly along a semicircle (see figure: equal… | Medium | |
| 133421 | (A classic way to compute …) A … needle is tossed onto… | Medium | |
| 133422 | If Buffon's needle has length … instead of 2, find the probability… | Medium | |
| 133424 | If you choose a random point in the square …, …, what… | Medium | |
| 133425 | The voltage … has frequency 60 hertz and amplitude 220 volts | Medium | |
| 133482 | These four integrals all equal …: …\int_0^1 \frac{dx}{\sqrt{x(1-x)}}\int_{-\infty}^\infty \frac{\sin x}{x}dx\frac{8}{3}\int_0^\pi \sin^4 x… | Medium | |
| 133484 | Compare … with … for … and | Medium | |
| 133486 | For the periodic function … from … to …, compare … and… | Medium | |
| 133488 | Change to …, …, …, and repeat … on | Medium | |
| 133490 | Can you invent a rule using … to reach higher accuracy than… | Medium | |
| 133492 | Calculate … with ten intervals from 0 to 5 and 0 to… | Medium | |
| 133493 | The graph of … has a sharp spike and a long tail | Medium | |
| 133239 | A pessimist would use … at the ____ of each time period… | Medium | |
| 133241 | At every step from years to weeks to days to hours, the… | Medium | |
| 133245 | The expenses drop to zero at … ____ | Medium | |
| 133246 | The rectangles of heights … give a total estimated expense of ____ | Medium | |
| 133247 | How many rectangles (enclosing the triangle) would you need before their areas… | Medium | |
| 133268 | … (find all …) | Medium | |