Before you startAI-drafted · not yet reviewed by an editor
To maximise or minimise a quantity that depends on a variable, turn the problem into a function and use calculus. First write the quantity (area, volume, cost, etc.) as a function . Then find its derivative and locate the points where – these are the *critical points*. Finally, decide whether each critical point gives a maximum, a minimum, or neither by checking the sign of on either side (the first‑derivative test) or by using the second derivative . The largest (or smallest) value of among the admissible critical points and any boundary values is the optimum.
Practice
44,994Endless problems made on demand, each with an exactly computed answer. Every click is a new one.
Curated
3| # | Title | Difficulty | Tags | |
|---|---|---|---|---|
| 83 | Where a cubic turnsExtrema | Easy | ||
| 82 | The open boxOptimization | Medium | ||
| 85 | The cheapest canOptimization | Medium |
From open sources
46Complete problems only, with worked solutions first. Show everything