Before you startAI-drafted · not yet reviewed by an editor
For a second-order linear homogeneous equation , try solutions of the form . Substitution gives the characteristic equation . If its roots are real and distinct, the general solution is . If there is a repeated root , the general solution is . If the roots are complex , the general solution is . Use the initial conditions to solve for and .
Curated
8| # | Title | Difficulty | Tags | |
|---|---|---|---|---|
| 170 | A spring, released | Easy | ||
| 395 | Characteristic roots | Easy | ||
| 396 | Released from rest at the centre | Easy | ||
| 399 | Exponential forcing | Easy | ||
| 400 | Constant forcing | Easy | ||
| 402 | The Wronskian | Easy | ||
| 403 | Natural frequency | Easy | ||
| 404 | How damped? | Easy |