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Count all equally likely outcomes and count the outcomes that satisfy the condition. The probability is the number of favorable outcomes divided by the total number of outcomes: \(P(E)=\frac{\text{favorable outcomes}}{\text{total outcomes}}\). For example, rolling two dice gives \(6\times6=36\) equally likely pairs. The pairs summing to 7 are \((1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\), six favorable outcomes, so \(P(\text{sum }7)=\frac{6}{36}=\frac16\). For "at least one" events, it is often easier to count the complement: outcomes where the event does not happen, then subtract from the total.
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14Complete problems only, with worked solutions first. Show everything
| # | Title | Difficulty | |
|---|---|---|---|
| 106276 | Sequences and Their Notations · Exercise 71 | Deep | |
| 106372 | Arithmetic Sequences · Exercise 76 | Deep | |
| 106449 | Geometric Sequences · Exercise 60 | Deep | |
| 106753 | Probability · Exercise 53 | Deep | |
| 106755 | Probability · Exercise 55 | Deep | |
| 106278 | Sequences and Their Notations · Exercise 73 | Deep | |
| 106370 | Arithmetic Sequences · Exercise 74 | Deep | |
| 106447 | Geometric Sequences · Exercise 58 | Deep | |
| 106451 | Geometric Sequences · Exercise 62 | Deep | |
| 106536 | Series and Their Notations · Exercise 56 | Deep | |
| 106538 | Series and Their Notations · Exercise 58 | Deep | |
| 106540 | Series and Their Notations · Exercise 60 | Deep | |
| 106542 | Series and Their Notations · Exercise 62 | Deep | |
| 106757 | Probability · Exercise 57 | Deep |